mathnodebase: use func ptr instead of switch inside loop
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@@ -167,42 +167,58 @@ void MathNodeBase::PushVector(NodeValueTable *output, olive::NodeValue::Type typ
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}
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}
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void MathNodeBase::PerformAllOnFloatBuffer(Operation operation, float *a, float b, int start, int end)
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{
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for (int j=start;j<end;j++) {
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a[j] = PerformAll(operation, a[j], b);
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}
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}
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#ifdef Q_PROCESSOR_X86
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typedef __m128 (*SSEOperationFunction)(__m128 a, __m128 b);
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void MathNodeBase::PerformAllOnFloatBufferSSE(Operation operation, float *a, float b, int start, int end)
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{
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int end_divisible_4 = (end / 4) * 4;
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// loop over 'a' and compare current elements with min and max 4 by 4.
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// we need to make sure we don't read out of boundaries should 'a' lenght be not mod. 4
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// Load number to multiply by into buffer
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__m128 mult = _mm_load1_ps(&b);
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for(int j = 0; j < end_divisible_4; j+=4) {
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__m128 cur = _mm_loadu_ps(a + start + j);
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__m128 res;
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// Switch statement doesn't seem to cause additional overhead, hopefully the compiler is
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// unrolling the loops?
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switch (operation) {
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case kOpAdd:
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res = _mm_add_ps(cur, mult);
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break;
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case kOpSubtract:
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res = _mm_sub_ps(cur, mult);
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break;
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case kOpMultiply:
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case kOpPower: // Technically incorrect but why would someone ever need this?
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res = _mm_mul_ps(cur, mult);
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break;
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case kOpDivide:
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res = _mm_div_ps(cur, mult);
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break;
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}
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_mm_storeu_ps(a + start + j, res);
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SSEOperationFunction func = nullptr;
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switch (operation) {
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case kOpAdd:
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func = _mm_add_ps;
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break;
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case kOpSubtract:
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func = _mm_sub_ps;
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break;
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case kOpMultiply:
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func = _mm_mul_ps;
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break;
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case kOpDivide:
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func = _mm_div_ps;
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break;
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case kOpPower:
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// Leave as nullptr, which will fallback to non-SSE operation
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break;
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}
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// Do last three numbers, if non-divisible by 4
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for (int j=end_divisible_4; j<end; j++) {
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a[j] *= b;
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if (func) {
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// If we have an SSE version of this operation, do this now
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// Loop all values
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for(int j = 0; j < end_divisible_4; j+=4) {
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__m128 cur = _mm_loadu_ps(a + start + j);
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__m128 res = func(cur, mult);
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_mm_storeu_ps(a + start + j, res);
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}
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// Do last three numbers, if non-divisible by 4
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for (int j=end_divisible_4; j<end; j++) {
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a[j] *= b;
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}
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} else {
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// Fallback for operations we can't support here
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PerformAllOnFloatBuffer(operation, a, b, start, end);
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}
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}
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#endif
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@@ -397,9 +413,7 @@ void MathNodeBase::ValueInternal(Operation operation, Pairing pairing, const QSt
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// Use SSE instructions for optimization
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PerformAllOnFloatBufferSSE(operation, job.samples()->data(i), number, 0, job.samples()->sample_count());
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#else
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for (int j=0;j<job.samples()->sample_count();j++) {
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job.samples()->data(i)[j] = PerformAll(operation, job.samples()->data(i)[j], number);
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}
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PerformAllOnFloatBuffer(operation, job.samples()->data(i), number, 0, job.samples()->sample_count());
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#endif
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}
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}
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@@ -102,6 +102,7 @@ protected:
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static T PerformAddSubMultDiv(Operation operation, T a, U b);
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#ifdef Q_PROCESSOR_X86
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static void PerformAllOnFloatBuffer(Operation operation, float *a, float b, int start, int end);
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static void PerformAllOnFloatBufferSSE(Operation operation, float *a, float b, int start, int end);
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#endif
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